Remove all characters after a certain match

Question

I am using Notepad++ to remove some unwanted strings from the end of a pattern and this for the life of me has got me.

I have the following sets of strings:

myApp.ComboPlaceHolderLabel,
myApp.GridTitleLabel);
myApp.SummaryLabel + '</b></div>');
myApp.NoneLabel + ')') + '</label></div>';

I would like to leave just myApp.[variable] and get rid of, e.g. ,, );, + '...', etc.

Using Notepad++, I can match the strings themselves using ^myApp.[a-zA-Z0-9].*?\b (it's a bit messy, but it works for what I need).

But in reality, I need negate that regex, to match everything at the end, so I can replace it with a blank.

Answer 1

You don't need to go for negation. Just put your regex within capturing groups and add an extra .*$ at the last. $ matches the end of a line. All the matched characters(whole line) are replaced by the characters which are present inside the first captured group. . matches any character, so you need to escape the dot to match a literal dot.

^(myApp\.[a-zA-Z0-9].*?\b).*$

Replacement string:

\1

DEMO

OR

Match only the following characters and then replace it with an empty string.

\b[,); +]+.*$

DEMO