Remove a line with a specific pattern in one field

Question

Below is my input file, input.txt:

Value Value1 value2
5 1 2
1 4 3
2 1 5.5
0 0 0
4 1 0

I need to search the value(5.5) in the 3rd column, if found i need to remove the row entirely.

And i need the output like below, output.txt:

Value Value1 value2
5 1 2
1 4 3
0 0 0
4 1 0

i have tried awk command to remove the row, but I'm stuck with the below part(???). Don't to how to remove the row entire row from awk command. please suggest way to achieve this. Thanks!
awk -F"\t" '{if($3==5.5) ??? }'

Answer 1

If you want exclude all lines with 3rd column's value 5.5 then:

awk '$3!=5.5' filename

Answer 2

GNU safer sed

sed -r '/\s*(\S+\s+){2}5.5/d' file