Regular expression usage in glob.glob?

Question

import glob  list = glob.glob(r'*abc*.txt') + glob.glob(r'*123*.txt') + glob.glob(r'*a1b*.txt')  for i in list:   print i 

This code works to list files in the current folder which have 'abc', '123' or 'a1b' in their names.

How would I use one glob to perform this function?

Answer 1

The easiest way would be to filter the glob results yourself. Here is how to do it using a simple loop comprehension:

import glob res = [f for f in glob.glob("*.txt") if "abc" in f or "123" in f or "a1b" in f] for f in res:     print f 

You could also use a regexp and no glob:

import os import re res = [f for f in os.listdir(path) if re.search(r'(abc|123|a1b).*\.txt$', f)] for f in res:     print f 

(By the way, naming a variable list is a bad idea since list is a Python type...)

Answer 2

I'm surprised that no answers here used filter.

import os import re  def glob_re(pattern, strings):     return filter(re.compile(pattern).match, strings)  filenames = glob_re(r'.*(abc|123|a1b).*\.txt', os.listdir()) 

This accepts any iterator that returns strings, including lists, tuples, dicts(if all keys are strings), etc. If you want to support partial matches, you could change .match to .search. Please note that this obviously returns a generator, so if you want to use the results without iterating over them, you could convert the result to a list yourself, or wrap the return statement with list(...).