I'm trying to write a regular expression that validates a date. The regex needs to match the following
So far I have
^(([1-9]|1[012])[-/.]([1-9]|[12][0-9]|3[01])[-/.](19|20)\d\d)|((1[012]|0[1-9])(3[01]|2\d|1\d|0[1-9])(19|20)\d\d)|((1[012]|0[1-9])[-/.](3[01]|2\d|1\d|0[1-9])[-/.](19|20)\d\d)$
This matches properly EXCEPT it still includes 2/30/2008 & 2/31/2008.
Does anyone have a better suggestion?
Edit: I found the answer on RegExLib
^((((0[13578])|([13578])|(1[02]))[\/](([1-9])|([0-2][0-9])|(3[01])))|(((0[469])|([469])|(11))[\/](([1-9])|([0-2][0-9])|(30)))|((2|02)[\/](([1-9])|([0-2][0-9]))))[\/]\d{4}$|^\d{4}$
It matches all valid months that follow the MM/DD/YYYY format.
Thanks everyone for the help.
No, if you are strictly speaking about regular expressions and not including some regular expression implementations that are actually context free grammars. There is one limitation of regular expressions which makes it impossible to write a regex that matches all and only regexes.
$ means "Match the end of the string" (the position after the last character in the string).
A regular expression for dates (YYYY-MM-DD) should check for 4 digits at the front of the expression, followed by a hyphen, then a two-digit month between 01 and 12, followed by another hyphen, and finally a two-digit day between 01 and 31.
This is not an appropriate use of regular expressions. You'd be better off using
[0-9]{2}/[0-9]{2}/[0-9]{4}
and then checking ranges in a higher-level language.
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