Regular expression to find bcrypt hash?

Question

I am looking to find bcrypt hash string using regex (in PowerGrep), in a database.

Tried this regex:

{?A-Za-z_0-9.{60}}?

But no match was found. Bcrypt hash is 60 characters length, and starts with "$2y$".

Example:

$2y$15$nK/B6u765645/lo0867h56546v/BnH5U5g45Aj67u67nMVtrhryt6

Answer 1

Just as an addition to the answer above from @stribizhev. The bcrypt hashes you might encounter out there in the wild come in a few varieties, so you may have to modify the regex to catch all of them. The variations are as follows:

The "Algorithm Identifier" portion of the hash may include:

• "2" - the first revision of BCrypt, which suffers from a minor security flaw and is generally not used anymore.

• "2a" - some implementations suffered from a very rare security flaw.

• "2y" - format specific to the crypt_blowfish BCrypt implementation, identical to "2a" in all but name.

• "2b" - latest revision of the official BCrypt algorithm

^\$2[ayb]\$.{56}$

seems to work for me

see here for the breakdown of a bcrypt hash: Can someone explain how BCrypt verifies a hash?

Answer 2

Update:

Since beside the y value there might be a or b, you may use

^\$2[ayb]\$.{56}$

See the regex demo online. Details:

• ^ - start of a string
• \$ - a literal $ char (it should be escaped in a regex pattern to match a literal $ char, else, it will denote the end of string)
• 2 - a 2 char
• [ayb] - a character class matching any single char out of the specified set
• \$ - a $ char
• .{56} - any 56 chars other than line break chars (if not POSIX compliant regex engine is used, else, it will match any chars; to match any chars in common NFA engines, replace . with [\s\S] or use a corresponding DOTALL flag)
• $ - end of string.

Original answer

Your regex - {?A-Za-z_0-9.{60}}? - contains ranges not inside a character class [...], but inside optional curly braces, and thus they present sequences of literal characters. See your regex demo to see what I mean.

You can use the following regex:

^\$2y\$.{56}$

See demo

The ^ matches the start of string, \$2y\$ matches $2y$ literally (as $ is a special character and needs escaping) and .{56} is the rest 56 characters.

Answer 3

Use this:

^\$2[aby]?\$\d{1,2}\$[.\/A-Za-z0-9]{53}$

Explanation:

• \$2[aby]?\$ - matches the algorithm used. Valid values are 2, 2a, 2y and 2b
• \d{1,2}\$ - matches the cost, or how many rounds, which is an integer between 4 and 31 (inclusive)
• [.\/A-Za-z0-9]{53} - matches the salt and the hash, with the salt making up the first 22 characters, and the hashed password making up the last 31