I'm looking for a regular expression that checks whether a string contains 2 specific words.
e.g. Whether the string contains rooster
or hen
.
However, to recognize multiple words in any order using regex, I'd suggest the use of quantifier in regex: (\b(james|jack)\b. *){2,} . Unlike lookaround or mode modifier, this works in most regex flavours.
The ?! n quantifier matches any string that is not followed by a specific string n.
The character + in a regular expression means "match the preceding character one or more times". For example A+ matches one or more of character A. The plus character, used in a regular expression, is called a Kleene plus .
The expresssion to match rooster
or hen
as a complete word (i.e. not when they are part of a longer, different word):
\b(rooster|hen)\b
This is a safety measure to avoid false positives with partial matches.
The \b
denotes a word boundary, which is the (zero-width) spot between a character in the range of "word characters" ([A-Za-z0-9_]
) and any other character. In effect the above would:
"A chicken is either a rooster or a hen."
"Chickens are either a roosters or hens."
- but (rooster|hen)
wouldAs a side note, to allow the plural, this would do: \b(roosters?|hens?)\b
Use |
for alternatives. In your case it's: (rooster|hen)
I had a similar requirement but it should only contain a particular word (from a list) and no other words should be present in the string. I had to use ^(rooster|hen)$
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With