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I am using Python and would like to match all the words after test till a period (full-stop) or space is encountered.
text = "test : match this."
At the moment, I am using :
import re
re.match('(?<=test :).*',text)
The above code doesn't match anything. I need match this as my output.
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Method 1: Match everything after first occurence Whitespace characters include spaces, tabs, linebreaks, etc. while non-whitespace characters include all letters, numbers, and punctuation. So essentially, the \s\S combination matches everything.
To run a “whole words only” search using a regular expression, simply place the word between two word boundaries, as we did with ‹ \bcat\b ›. The first ‹ \b › requires the ‹ c › to occur at the very start of the string, or after a nonword character.
The dot matches all except newlines (\r\n). So use \s\S, which will match ALL characters.
. Your regex starts with (?= (ensure that you can see, but don't consume) followed by . * (zero or more of any character).
Everything after test, including test
test.*
Everything after test, without test
(?<=test).*
Example here on regexr.com
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