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I'm finding a regular expression which adheres below rules.
Allowed Characters
Alphabet : a-z / A-Z
Numbers : 0-9
Special Characters : ~ @ # $ ^ & * ( ) - _ + = [ ] { } | \ , . ? :
(spaces should be allowed)
Not Allowed
Special Characters : < > ' " / ; ` %
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var nospecial=/^[^* | \ " : < > [ ] { } ` \ ( ) '' ; @ & $]+$/; if(address. match(nospecial)){ alert('Special characters like * | \ " : < > [ ] { } ` \ ( ) \'\' ; @ & $ are not allowed'); return false; but it is not working.
The ?! n quantifier matches any string that is not followed by a specific string n.
This answer is not useful. Show activity on this post. [] denotes a character class. () denotes a capturing group. [a-z0-9] -- One character that is in the range of a-z OR 0-9.
For the allowed characters you can use
^[a-zA-Z0-9~@#$^*()_+=[\]{}|\\,.?: -]*$ to validate a complete string that should consist of only allowed characters. Note that - is at the end (because otherwise it'd be a range) and a few characters are escaped.
For the invalid characters you can use
[<>'"/;`%] to check for them.
To combine both into a single regex you can use
^(?=[a-zA-Z0-9~@#$^*()_+=[\]{}|\\,.?: -]*$)(?!.*[<>'"/;`%]) but you'd need a regex engine that allows lookahead.
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