I'm trying to replace a set of words in a text string. Now I have a loop, which does not perform well:
function clearProfanity(s) {
var profanity = ['ass', 'bottom', 'damn', 'shit'];
for (var i=0; i < profanity.length; i++) {
s = s.replace(profanity[i], "###!");
}
return s;
}
I want something that works faster, and something that will replace the bad word with a ###!
mark having the same length as the original word.
Here's one way to do it:
String.prototype.repeat = function(n){
var str = '';
while (n--){
str+=this;
}
return str;
}
var re = /ass|bottom|damn|shit/gi
, profane = 'my ass is @ the bottom of the sea, so shit \'nd damn';
alert(profane.replace(re,function(a) {return '#'.repeat(a.length)}));
//=>my ### is @ the ###### of the sea, so #### 'n ####
To be complete: here's a simpler way to do it, taking word boundaries into account:
var re = /\W+(ass|shit|bottom|damn)\W+/gi
, profane = [ 'My cassette of forks is at the bottom'
,'of the sea, so I will be eating my shitake'
,'whith a knife, which can be quite damnable'
,'ambassador. So please don\'t harrass me!'
,'By the way, did you see the typo'
,'in "we are sleepy [ass] bears"?']
.join(' ')
.replace( re,
function(a){
return a.replace(/[a-z]/gi,'#');
}
);
alert(profane);
See it working: http://jsfiddle.net/osher/ZnJ5S/3/
Which basically is:
var PROFANITY = ['ass','bottom','damn','shit']
, CENZOR = ("#####################").split("").join("########")
;
PROFANITY = new RegExp( "(\\W)(" + PROFANITY.join("|") + ")(\\W)","gi");
function clearProfanity(s){
return s.replace( PROFANITY
, function(_,b,m,a) {
return b + CENZOR.substr(0, m.length - 1) + "!" + a
}
);
}
alert( clearProfanity("'ass','bottom','damn','shit'") );
It would be better if the PROFANITY
array would be initiated as a string, or better - directly as a Regular Expression:
//as string
var PROFANITY = "(\\W)(ass|bottom|damn|shit)(\\W)";
PROFANITY = new RegExp(PROFANITY, "gi");
//as regexp
var PROFANITY = /(\W)(ass|bottom|damn|shit)(\W)/gi
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