Regular Expression for a string that contains one or more letters somewhere in it

Question

What would be a regular expression that would evaluate to true if the string has one or more letters anywhere in it.

For example:

1222a3999 would be true

a222aZaa would be true

aaaAaaaa would be true

but:

1111112())-- would be false

I tried: ^[a-zA-Z]+$ and [a-zA-Z]+ but neither work when there are any numbers and other characters in the string.

Answer 1

.*[a-zA-Z].*

The above means one letter, and before/after it - anything is fine.

In java:

String regex = ".*[a-zA-Z].*";
System.out.println("1222a3999".matches(regex));
System.out.println("a222aZaa ".matches(regex));
System.out.println("aaaAaaaa ".matches(regex));
System.out.println("1111112())-- ".matches(regex));

Will provide:

true
true
true
false

as expected