Regular Expression: Any character that is NOT a letter or number

Question

To match anything other than letter or number you could try this:

[^a-zA-Z0-9]

And to replace:

var str = 'dfj,dsf7lfsd .sdklfj';
str = str.replace(/[^A-Za-z0-9]/g, ' ');

This regular expression matches anything that isn't a letter, digit, or an underscore (_) character.

\W

For example in JavaScript:

"(,,@,£,() asdf 345345".replace(/\W/g, ' '); // Output: "          asdf 345345"

You are looking for:

var yourVar = '1324567890abc§$)%';
yourVar = yourVar.replace(/[^a-zA-Z0-9]/g, ' ');

This replaces all non-alphanumeric characters with a space.

The "g" on the end replaces all occurrences.

Instead of specifying a-z (lowercase) and A-Z (uppercase) you can also use the in-case-sensitive option: /[^a-z0-9]/gi.

This is way way too late, but since there is no accepted answer I'd like to provide what I think is the simplest one: \D - matches all non digit characters.

var x = "123 235-25%";
x.replace(/\D/g, '');

Results in x: "12323525"

See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Regular_Expressions

• Match letters only /[A-Z]/ig
• Match anything not letters /[^A-Z]/ig
• Match number only /[0-9]/g or /\d+/g
• Match anything not number /[^0-9]/g or /\D+/g
• Match anything not number or letter /[^A-Z0-9]/ig

There are other possible patterns

try doing str.replace(/[^\w]/); It will replace all the non-alphabets and numbers from your string!

Edit 1: str.replace(/[^\w]/g, ' ')