Regex.Match goups includes full string, how to exclude

Question

I have the following code;

var pattern = "(\".*\") (\".*\")";
var regex = Regex.Match(input, pattern);

The value for input would be similar to this;

"string part1" "string part2"

The regex groups include the following

groups[0] = "string part1" "string part2"
groups[1] = "string part1"
groups[2] = "string part2"

Is there a way to exclude groups[0] as I simply want to concatenate the strings while removing the " " between them so that it becomes;

"string part1string part2"

Answer 1

Use LINQ .Skip(1) on the values you have in groups. Then, concat the rest of the items:

var input = "\"string part1\" \"string part2\"";
var pattern = "\"(.*)\" \"(.*)\"";
var match = Regex.Match(input, pattern);
if (match.Success) 
{
    Console.WriteLine("\"{0}\"",
        string.Join(
            " ",
            match.Groups
              .Cast<Group>()
              .Select(x=>x.Value)
              .Skip(1)
        )
    );
}

See the C# demo online.

Note I also moved the capturing group bounds inside the quotes to get rid of the quotation marks in the group values.

Also, consider an alternative pattern in case you want to match substrings between the closest quotes: var pattern = "\"([^\"]*)\" \"([^\"]*)\"";.