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I have numbers like this that need leading zero's removed.
Here is what I need:
00000004334300343 -> 4334300343
0003030435243 -> 3030435243
I can't figure this out as I'm new to regular expressions. This does not work:
(^0)
652
Use the inbuilt replaceAll() method of the String class which accepts two parameters, a Regular Expression, and a Replacement String. To remove the leading zeros, pass a Regex as the first parameter and empty string as the second parameter. This method replaces the matched value with the given string.
$ means "Match the end of the string" (the position after the last character in the string).
If you are having a string with special characters and want's to remove/replace them then you can use regex for that. Use this code: Regex. Replace(your String, @"[^0-9a-zA-Z]+", "")
str. erase(0, min(str. find_first_not_of('0'), str. size()-1));
You're almost there. You just need quantifier:
str = str.replaceAll("^0+", "");
It replaces 1 or more occurrences of 0 (that is what + quantifier is for. Similarly, we have * quantifier, which means 0 or more), at the beginning of the string (that's given by caret - ^), with empty string.
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