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Regex to split string

Tags:

java

regex

split

I have this code which prints:

[( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), ( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]

I tried to split at [#] but it didnt work.

What should i put in split so that I can get as a result the part after # only: Hello, Bye

Query query = QueryFactory.create(queryString);
                     QueryExecution qe= QueryExecutionFactory.create(query, model);
                    ResultSet resultset = qe.execSelect();
                    ResultSet results = ResultSetFactory.copyResults(resultset); 
                    final ResultSet results2 = ResultSetFactory.copyResults(results);


                    System.out.println( "== Available Options ==" );
                    ResultSetFormatter.out(System.out, results, query);



    Scanner input = new Scanner(System.in);
    final String inputs;
    inputs = input.next();
    final String[] indices = inputs.split("\\s*,\\s*");

    final List<QuerySolution> selectedSolutions = new ArrayList<QuerySolution>(
            indices.length) {
        {
            final List<QuerySolution> solutions = ResultSetFormatter
                    .toList(results2);
            for (final String index : indices) {
                add(solutions.get(Integer.valueOf(index)));
            }
        }
    };

    System.out.println(selectedSolutions);
like image 984
user2598911 Avatar asked Jul 11 '26 02:07

user2598911


1 Answers

If I understand correctly, you only want to extract "Hello" and "Bye" from your input String through regex.

In which case, I would just use iterative matching of whatever's in between # and >, as such:

// To clarify, this String is just an example
// Use yourScannerInstance.nextLine to get the real data
String input = "[( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), "
                + "( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]";
// Pattern improved by Brian
// was: #(.+?)>
Pattern p = Pattern.compile("#([^>]+)>");
Matcher m = p.matcher(input);
// To clarify, printing the String out is just for testing purpose
// Add "m.group(1)" to a Collection<String> to use it in further code
while (m.find()) {
    System.out.println(m.group(1));
}

Output:

Hello
Bye
like image 152
Mena Avatar answered Jul 14 '26 17:07

Mena



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