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How can i say "all symbols except backslash" in Ruby character class?
/'[^\]*'/.match("'some string \ hello'") => should be nil
Variant with two backslashed doesn't work
/'[^\\]*'/.match("'some string \ hello'") => 'some string \ hello' BUT should be nil
388
1. Match any character using regex Pattern Description “.” Matches only a single character. “A.B” Matches any character at second place in ... “.*” Matches any number of characters.
How do I match any characters except a double-quote NOT preceded by a backslash? So: match quotes, and inside them: every character except a quote ( [^"]) or an escaped quote ( " ), arbitrarily many times ( * ). As chaos mentioned, you probably also want to handle double-backslashes separately (although that wasn't specified by the OP).
By default, the '.' dot character in a regular expression matches a single character without regard to what character it is. The matched character can be an alphabet, a number or, any special character. To create more meaningful patterns, we can combine the dot character with other regular expression constructs. .
A character class allows one to specify a specific set (or class) of characters that are allowed at a particular location within a match. The set of characters is enclosed by an opening [ Edit with Regexity and closing ] Edit with Regexity square bracket.
Your problem is not with your regex; you got that right. Your problem is that your test string does not have a backslash in it. It has an escaped space, instead. Try this:
str = "'some string \\ hello'"
puts str #=> 'some string \ hello'
p /'[^\\]*'/.match(str) #=> nil
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