Regex to check for new line

Question

I want to check if an if statement is on one line or the next line without a brace like so:

if (blah === blah)
    do something

or:

if (foo === foo) do something

The regex i have currently is

/\)(?!.*\{)/

But doesnt work. Anyone have any ideas?

To elaborate the only If statement that would not be pulled by this regex is the following:

if (foo === bar)
{

Answer 1

simple \r \n (carriage return and new line)

/[\r\n]/

Answer 2

New lines may be \n (UNIX), \r\n (Windows), \r (for good measure). The expression to broadly match new lines is:

/\r\n|\r|\n/

To check if an expression is on one line, you can do this:

if( preg_match( '/\r\n|\r|\n/', $string ) ) {
    // on more than one line
    ...
} else {
   // on one line
   ...
}

To further develop this to apply to your specific example of an if ... do statement, you could do this:

if( preg_match( '/if *\([^\)]+\) *(\r\n|\r|\n) *do /', $string ) ) {
    // on more than one line
    ...
} elseif( preg_match( '/if *\([^\)]+\) *do /', $string ) ) {
   // on one line
   ...
}

Answer 3

You need to make . match newlines, too:

/\)(?!.*\{)/s
            ^
    PCRE_DOTALL Modifier

This is done with the s (PCRE_DOTALL ) modifier (as written in comments):

s (PCRE_DOTALL)

If this modifier is set, a dot metacharacter in the pattern matches all characters, including newlines. Without it, newlines are excluded. This modifier is equivalent to Perl's /s modifier. A negative class such as [^a] always matches a newline character, independent of the setting of this modifier.