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How can I use PHP to strip out all characters that are NOT alpha, numeric, space, or puncutation?
I've tried the following, but it strip punctuation.
preg_replace("/[^a-zA-Z0-9\s]/", "", $str); 
373
You can use the regular expression [^a-zA-Z0-9] to identify non-alphanumeric characters in a string and replace them with an empty string. Use the regular expression [^a-zA-Z0-9 _] to allow spaces and underscore character. The word characters in ASCII are [a-zA-Z0-9_] .
Using Regular Expression We can use the regular expression [^a-zA-Z0-9] to identify non-alphanumeric characters in a string. Replace the regular expression [^a-zA-Z0-9] with [^a-zA-Z0-9 _] to allow spaces and underscore character.
Non-alphanumeric characters comprise of all the characters except alphabets and numbers. It can be punctuation characters like exclamation mark(!), at symbol(@), commas(, ), question mark(?), colon(:), dash(-) etc and special characters like dollar sign($), equal symbol(=), plus sign(+), apostrophes(').
preg_replace("/[^a-zA-Z0-9\s\p{P}]/", "", $str); Example:
php > echo preg_replace("/[^a-zA-Z0-9\s\p{P}]/", "", "⟺f✆oo☃. ba⟗r!"); foo. bar! \p{P} matches all Unicode punctuation characters (see Unicode character properties). If you only want to allow specific punctuation, simply add them to the negated character class. E.g:
preg_replace("/[^a-zA-Z0-9\s.?!]/", "", $str); You're going to have to list the punctuation explicitly as there is no shorthand for that (eg \s is shorthand for white space characters).
preg_replace('/[^a-zA-Z0-9\s\-=+\|!@#$%^&*()`~\[\]{};:\'",<.>\/?]/', '', $str); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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