RegEx pattern any two letters followed by six numbers

Question

Please assist with the proper RegEx matching any 2 letters followed by any combination of 6 whole numbers.

These would be valid:  RJ123456 PY654321 DD321234  These would not DDD12345 12DDD123 

Answer 1

[a-zA-Z]{2}\d{6}

[a-zA-Z]{2} means two letters \d{6} means 6 digits

If you want only uppercase letters, then:

[A-Z]{2}\d{6}

Answer 2

You could try something like this:

[a-zA-Z]{2}[0-9]{6} 

Here is a break down of the expression:

[a-zA-Z]    # Match a single character present in the list below                # A character in the range between “a” and “z”                # A character in the range between “A” and “Z”    {2}         # Exactly 2 times [0-9]       # Match a single character in the range between “0” and “9”    {6}         # Exactly 6 times 

This will match anywhere in a subject. If you need boundaries around the subject then you could do either of the following:

^[a-zA-Z]{2}[0-9]{6}$ 

Which ensures that the whole subject matches. I.e there is nothing before or after the subject.

or

\b[a-zA-Z]{2}[0-9]{6}\b 

which ensures there is a word boundary on each side of the subject.

As pointed out by @Phrogz, you could make the expression more terse by replacing the [0-9] for a \d as in some of the other answers.

[a-zA-Z]{2}\d{6}