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I'm trying to match whole line of text starting from !
with regex.
I made something like this: /(!\w+\s+\S+)/ig which is pretty close, but only for 2 words. I would like to match words upto new line. Also I see problem with spoiler in the middle of sentence.
Live example: http://www.rubular.com/r/MXmholsDwE
691
Search without case sensitivity. If an exclamation mark (!) occurs as the first character in a regular expression, all magic characters are treated as special characters. An exclamation mark is treated as a regular character if it occurs anywhere but at the very start of the regular expression.
To run a “whole words only” search using a regular expression, simply place the word between two word boundaries, as we did with ‹ \bcat\b ›. The first ‹ \b › requires the ‹ c › to occur at the very start of the string, or after a nonword character.
A word boundary \b is a test, just like ^ and $ . When the regexp engine (program module that implements searching for regexps) comes across \b , it checks that the position in the string is a word boundary.
\f stands for form feed, which is a special character used to instruct the printer to start a new page.
You just need
^!.*
See the updated regex demo
The ^ matches the start of a line (in Ruby), ! will match a literal ! and .* will match zero or more characters other than a newline (if you are using Ruby, which I assume from your use of the rubular Web site).
If you are using a regex flavor other than Ruby, like JS, or PHP, or .NET, you need to specify the /m - MULTILINE - modifier (e.g. /^!.*/gm in JavaScript).
172
If you want to match everything to the end of the line:
/(!.+)/
If you want to make sure that it follows the format !word---:
/!\w.+/
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