Regex matching quoted string but ignoring escaped quotation mark

Question

What I want to know is how to modify following regex: \".*?\" so it will ignore escaped " character (\") so it won't end matching at \".

For example:

parameter1 =  "      fsfsdfsd \"      "   parameter2 =   "   fsfsfs   "

I want to match:

" fsfsdfsd \" "

and

" fsfsfs "

but not

" fsfsdfsd \" " parameter2 = " fsfsfs "

etc...

Answer 1

Try this one:

"(?:\\"|[^"])*"

It matches "test \" though(you can probably avoid that using lookbehind). Escape the character if you need using \

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