I want to be able to match the following examples:
www.example.com
http://example.com
https://example.com
I have the following regex which does NOT match www.
but will match http://
https://
. I need to match any prefix in the examples above and up until the next white space thus the entire URL.
var regx = ((\s))(http?:\/\/)|(https?:\/\/)|(www\.)(?=\s{1});
Lets say I have a string that looks like the following:
I have found a lot of help off www.stackoverflow.com and the people on there!
I want to run the matching on that string and get
www.stackoverflow.com
Thanks!
\s\d matches a whitespace character followed by a digit. [\s\d] matches a single character that is either whitespace or a digit. When applied to 1 + 2 = 3, the former regex matches 2 (space two), while the latter matches 1 (one).
[^ ] matches anything but a space character.
To match a literal space, you'll need to escape it: "\\ " . This is a useful way of describing complex regular expressions: phone <- regex(" \\(? #
The correct regex to use is ^\d+$. Because “start of string” must be matched before the match of \d+, and “end of string” must be matched right after it, the entire string must consist of digits for ^\d+$ to be able to match.
Take this regular expression: /^[^abc]/ . This will match any single character at the beginning of a string, except a, b, or *c. If you add a * after it – /^[^abc]*/ – the regular expression will continue to add each subsequent character to the result, until it meets either an a , or b , or c .
You can try
(?:www|https?)[^\s]+
Here is online demo
sample code:
var str="I have found a lot of help off www.stackoverflow.com and the people on there!";
var found=str.match(/(?:www|https?)[^\s]+/gi);
alert(found);
Pattern explanation:
(?: group, but do not capture:
www 'www'
| OR
http 'http'
s? 's' (optional)
) end of grouping
[^\s]+ any character except: whitespace
(\n, \r, \t, \f, and " ") (1 or more times)
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