regex match if starts or ends with whitespaces

Question

I need to match my string if it starts with any number of whitespaces or ends with any number of spaces:

my current regex includes also the spaces inbetween:

(^|\s+)|(\s+|$)

how can I fix it to reach my goal?

update:

this doesn't work, because it matches the spaces. I want to select the whole string or line rather, if it starts with or ends with whitespace(s).

Answer 1

modify it to the following

(^\s+)|(\s+$)

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Based on modified OP, Use this Pattern ^\s*(.*?)\s*$ Demo look at capturing group #1

^               # Start of string/line
\s              # <whitespace character>
*               # (zero or more)(greedy)
(               # Capturing Group (1)
  .             # Any character except line break
  *?            # (zero or more)(lazy)
)               # End of Capturing Group (1)
\s              # <whitespace character>
*               # (zero or more)(greedy)
$               # End of string/line

Answer 2

You can use this: https://regex101.com/r/gTQS5g/1

^\s|\s$

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Or with .trim() you could do without the regex:

myStr !== myStr.trim()

Answer 3

No need to create groups. You can create one alternation.

^\s+|\s+$

Live demo