I have a string like:
Today, 3:30pm - Group Meeting to discuss "big idea"
How do you construct a regex such that after parsing it would return:
Today 3:30pm Group Meeting to discuss big idea
I would like it to remove all non-alphanumeric characters except for those that appear in a 12 or 24 hour time stamp.
# this: D:DD, DD:DDam/pm 12/24 hr
re = r':(?=..(?<!\d:\d\d))|[^a-zA-Z0-9 ](?<!:)'
A colon must be preceded by at least one digit and followed by at least two digits: then it's a time. All other colons will be considered textual colons.
: // match a colon
(?=.. // match but not capture two chars
(?<! // start a negative look-behind group (if it matches, the whole fails)
\d:\d\d // time stamp
) // end neg. look behind
) // end non-capture two chars
| // or
[^a-zA-Z0-9 ] // match anything not digits or letters
(?<!:) // that isn't a colon
Then when applied to this silly text:
Today, 3:30pm - Group 1,2,3 Meeting to di4sc::uss3: 2:3:4 "big idea" on 03:33pm or 16:47 is also good
...changes it into:
Today, 3:30pm Group 123 Meeting to di4scuss3 234 big idea on 03:33pm or 16:47 is also good
Python.
import string
punct=string.punctuation
s='Today, 3:30pm - Group Meeting:am to discuss "big idea" by our madam'
for item in s.split():
try:
t=time.strptime(item,"%H:%M%p")
except:
item=''.join([ i for i in item if i not in punct])
else:
item=item
print item,
output
$ ./python.py
Today 3:30pm Group Meetingam to discuss big idea by our madam
# change to s='Today, 15:30pm - Group 1,2,3 Meeting to di4sc::uss3: 2:3:4 "big idea" on 03:33pm or 16:47 is also good'
$ ./python.py
Today 15:30pm Group 123 Meeting to di4scuss3 234 big idea on 03:33pm or 1647 is also good
NB: Method should be improved to check for valid time only when necessary(by imposing conditions) , but i will leave it as that for now.
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