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I wonder how i can exclude a substring from the result after it matches the pattern. example:
<a href="?page1"><?php __('string1');?></a>
<a href="?page2"><?php __("string2");?></a>
I want to get only the strings passed as parameters to the __() function. i tried this regex:
'/__\(((\'([^\']+)\')|(\"([^\"]+)\"))/'
but that returns 'string1' and "string2" wrapped in single quotes and double quotations.
how can i exclude single quotes and double quotations?
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Example: The regex "aa\n" tries to match two consecutive "a"s at the end of a line, inclusive the newline character itself. Example: "a\+" matches "a+" and not a series of one or "a"s. ^ the caret is the anchor for the start of the string, or the negation symbol.
To count a regex pattern multiple times in a given string, use the method len(re. findall(pattern, string)) that returns the number of matching substrings or len([*re. finditer(pattern, text)]) that unpacks all matching substrings into a list and returns the length of it as well.
Regular expressions, called regexes for short, are descriptions for a pattern of text. For example, a \d in a regex stands for a digit character — that is, any single numeral 0 to 9. Following regex is used in Python to match a string of three numbers, a hyphen, three more numbers, another hyphen, and four numbers.
You want to try using non-capturing groups - (?:ABC)
134
You can use Lookahead and Lookbehind or make the string inside of the quotes a group.
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