Menu
Is there an option to write a regex that represents strings that start with " and don't end with " ?
396
$ means "Match the end of the string" (the position after the last character in the string). Both are called anchors and ensure that the entire string is matched instead of just a substring.
[] denotes a character class. () denotes a capturing group. [a-z0-9] -- One character that is in the range of a-z OR 0-9. (a-z0-9) -- Explicit capture of a-z0-9 .
Basically (0+1)* mathes any sequence of ones and zeroes. So, in your example (0+1)*1(0+1)* should match any sequence that has 1. It would not match 000 , but it would match 010 , 1 , 111 etc. (0+1) means 0 OR 1. 1* means any number of ones.
Using regex \B-\B matches - between the word color - coded . Using \b-\b on the other hand matches the - in nine-digit and pass-key .
You can use the regex:
^".*[^"]$
Explanation:
^ Start of line anchor
" A literal "
.* Any junk
[^"] Any non " character
$ End of line anchor
There you go:
^".*[^"]$
^" starts with "
.* some chars (or none)
[^"]$ doesn't end with "
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
