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Regex for not containing consecutive characters

I can't figure out javascript regex that would satisfy all those requirements:

The string can only contain underscores and alphanumeric characters. It must begin with a letter, not include spaces, not end with an underscore, and not contain two consecutive underscores.

This is as far as I came, but 'not containing consecutive underscores' part is the hardest to add.

^[a-zA-Z][a-zA-Z0-9_]+[a-zA-Z0-9]$
like image 769
Mariusz Avatar asked Feb 14 '18 13:02

Mariusz


Video Answer


2 Answers

You could use multiple lookaheads (neg. ones in this case):

^(?!.*__)(?!.*_$)[A-Za-z]\w*$

See a demo on regex101.com.


Broken down this says:
^           # start of the line
(?!.*__)    # neg. lookahead, no two consecutive underscores (edit 5/31/20: removed extra Kleene star)
(?!.*_$)    # not an underscore right at the end
[A-Za-z]\w* # letter, followed by 0+ alphanumeric characters
$           # the end


As JavaScript snippet:

let strings = ['somestring', '_not_this_one', 'thisone_', 'neither this one', 'but_this_one', 'this__one_not', 'this_one__yes']

var re = /^(?!.*__)(?!.*_$)[A-Za-z]\w*$/;
strings.forEach(function(string) {
    console.log(re.test(string));
});

Please do not restrain passwords!

like image 66
Jan Avatar answered Sep 30 '22 16:09

Jan


You can also use

^[a-zA-Z]([a-zA-Z0-9]|(_(?!_)))+[a-zA-Z0-9]$

Demo

The only change comparing to your regex is changing [a-zA-Z0-9_] to [a-zA-Z0-9]|(_(?!_)). I removed underscore from the character set and allow it in the second part of the alternative if it's not followed by another one.

(?!_) is negative lookahead meaning that _ cannot be next character

like image 39
mrzasa Avatar answered Sep 30 '22 16:09

mrzasa