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I need a regular expression for replacing multiple forward slashes in a URL with a single forward slash, excluding the ones following the colon
e.g. http://link.com//whatever/// would become http://link.com/whatever/
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The forward slash character is used to denote the boundaries of the regular expression: ? The backslash character ( \ ) is the escaping character. It can be used to denote an escaped character, a string, literal, or one of the set of supported special characters.
@:%_\+~#= , to match the domain/sub domain name.
Basically (0+1)* mathes any sequence of ones and zeroes. So, in your example (0+1)*1(0+1)* should match any sequence that has 1. It would not match 000 , but it would match 010 , 1 , 111 etc. (0+1) means 0 OR 1. 1* means any number of ones.
Throw in an * (asterisk), and it will match everything. Read more. \s (whitespace metacharacter) will match any whitespace character (space; tab; line break; ...), and \S (opposite of \s ) will match anything that is not a whitespace character.
I think this should work: /[^:](\/+)/ or /[^:](\/\/+)/ if you want only multiples.
It wont match leading // but it looks like you're not looking for that.
To replace:
"http://test//a/b//d".replace(/([^:]\/)\/+/g, "$1") // --> http://test/a/b/d
Working Demo
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