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Ok, so this is something completely stupid but this is something I simply never learned to do and its a hassle.
How do I specify a string that does not contain a sequence of other characters. For example I want to match all lines that do NOT end in '.config'
I would think that I could just do
.*[^(\.config)]$ but this doesn't work (why not?)
I know I can do
.*[^\.][^c][^o][^n][^f][^i][^g]$ but please please please tell me that there is a better way
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Example: The regex "aa\n" tries to match two consecutive "a"s at the end of a line, inclusive the newline character itself. Example: "a\+" matches "a+" and not a series of one or "a"s. ^ the caret is the anchor for the start of the string, or the negation symbol.
Basically (0+1)* mathes any sequence of ones and zeroes. So, in your example (0+1)*1(0+1)* should match any sequence that has 1. It would not match 000 , but it would match 010 , 1 , 111 etc. (0+1) means 0 OR 1.
The Alphanumericals are a combination of alphabetical [a-zA-Z] and numerical [0-9] characters, 62 characters.
You can use negative lookbehind, e.g.:
.*(?<!\.config)$ This matches all strings except those that end with ".config"
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