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I am new to regex. I have this regex:
\[(.*[^(\]|\[)].*)\]
Basically it should take this:
[[a][b][[c]]]
And be able to replace with:
[dd[d]]
abc, d are unrelated. Needless to say the regex bit isn't working. it replaces the entire string with "d" in this case.
Any explanation or aid would be great!
EDIT:
I tried another regex,
\[([^\]]{0})\]
This one worked for the case where brackets contain no inner brackets and nothing else inside. But it doesn't work for the described case.
807
If you want to remove the [ or the ] , use the expression: "\\[|\\]" . The two backslashes escape the square bracket and the pipe is an "or".
The [] construct in a regex is essentially shorthand for an | on all of the contents. For example [abc] matches a, b or c. Additionally the - character has special meaning inside of a [] . It provides a range construct. The regex [a-z] will match any letter a through z.
Square brackets match something that you kind of don't know about a string you're looking for. If you are searching for a name in a string but you're not sure of the exact name you could use instead of that letter a square bracket. Everything you put inside these brackets are alternatives in place of one character.
Just make sure ] is the first character (or in this case, first after the ^ . result2 = Regex. Replace(result2, "[^][A-Za-z0-9/.,>#:\s]", "");
You need to know that . dot is special character which represents "any character beside new line mark" and * is greedy so it will try to find maximal match.
In your regex \[(.*[^(\]|\[)].*)\] first .* will represent maximal set of characters between [ and [^(\]|\[)].*)\]] and this part can be understood as non [ or ] character, optional other characters .* and finally ]. So this regex will match your entire input.
To get rid of that problem remove both .* from your regex. Also you don't need to use | or ( ) inside [^...].
System.out.println("[[a][b][[c]]]".replaceAll("\\[[^\\]\\[]\\]", "d"));
Output: [dd[d]]
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