I'm trying to write some general documentation for a module I've written and I wish to reference my operator<<
method from within the documentation.
I have distilled the problem down to a couple of example files.
C++ source
namespace outer {
namespace inner {
/** The example class is called Foo. */
class Foo
{
public:
/** Stream an int pointlessly to Foo.
* @param i Some integer that serves no purpose.
* @return The foo you invoked << upon.
*/
Foo& operator<< (int i)
{
return *this;
}
/** Foo always is and never is not. */
bool operator! ()
{
return false;
}
};
}
}
Markdown documentation:
Foo {#mainpage}
===
You can stream an int to @ref outer::inner::Foo "Foo" by using outer::inner::Foo::operator<<()
Did I mention you can stream an int to outer::inner::Foo by using @ref outer::inner::Foo::operator<<() "operator<<" ?
What about streaming an int with
@link outer::inner::Foo::operator<<()
operator <<
@endlink
Foo's always are, and never are not. outer::inner::Foo::operator!() tells you this.
I just said that @ref outer::inner::Foo::operator!() "operator!" tells you this.
When I run doxygen 1.8.4, the @ref
and @link
fail to resolve, with the reason being:
Warning: unable to resolve reference to `outer::inner::Foo::operator' for \ref command
Warning: unable to resolve link to `outer::inner::Foo::operator' for \link command
Autolinking to the operators works fine, but to make the documentation easier to read, I want to use @ref to remove the whole namespace and class prefixing.
At first I thought perhaps it was only to do with operator<<
but it appears to be a problem for all operator overloads.
Is there a way to achieve this? What am I doing wrong?
It seems one can currently only reference operators by using the full argument list. In your case this would be:
@ref outer::inner::Foo::operator<<(int) and @ref outer::inner::Foo::operator!()
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With