Alternatively, if you want to simply set the number of ticks while allowing matplotlib to position them (currently only with MaxNLocator
), there is pyplot.locator_params
,
pyplot.locator_params(nbins=4)
You can specify specific axis in this method as mentioned below, default is both:
# To specify the number of ticks on both or any single axes
pyplot.locator_params(axis='y', nbins=6)
pyplot.locator_params(axis='x', nbins=10)
If somebody still gets this page in search results:
fig, ax = plt.subplots()
plt.plot(...)
every_nth = 4
for n, label in enumerate(ax.xaxis.get_ticklabels()):
if n % every_nth != 0:
label.set_visible(False)
To solve the issue of customisation and appearance of the ticks, see the Tick Locators guide on the matplotlib website
ax.xaxis.set_major_locator(plt.MaxNLocator(3))
Would set the total number of ticks in the x-axis to 3, and evenly distribute it across the axis.
There is also a nice tutorial about this
There's a set_ticks()
function for axis objects.
in case somebody still needs it, and since nothing here really worked for me, i came up with a very simple way that keeps the appearance of the generated plot "as is" while fixing the number of ticks to exactly N:
import numpy as np
import matplotlib.pyplot as plt
f, ax = plt.subplots()
ax.plot(range(100))
ymin, ymax = ax.get_ylim()
ax.set_yticks(np.round(np.linspace(ymin, ymax, N), 2))
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