Redis: how to delete multiple keys matching pattern?

Question

I need to remove 10 000 keys.

1. What is better way: to exec this kind of script

   EVAL "return redis.call('del', unpack(redis.call('keys', ARGV[1])))" 0 "ROOT"

2. May be better is to set expiration time and Redis will remove them? But how to do it in console using Lua script?

The script (see above) works because del comman dhas a format:

del key1 key2 ...

But Expire works only for 1 key.

Is it possible to do it in lua script?

For example: my application creates some search results cache and set for every page ttl = 3600. But user wants to clear cache immediately, i.e. delete all matching keys or set smaller expiration for them.

Answer 1

You can either use (from redis cli) to delete all keys:

flushall

or run this from your command line (bash)

redis-cli --scan --pattern aihello_user* | xargs redis-cli del