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How can I draw a rectangle with a gradient effect like the one pictured below using the HTML5 canvas element?
Edit: Thanks for all the feedback. Yes, I have already tried many methods. For example, can I use the createRadialGradient method as @Loktar suggests? Here is some sample code:
<html>
<head>
<title>test</title>
<script type="application/x-javascript">
function draw() {
var canvas = document.getElementById("canvas"),
ctx = canvas.getContext("2d");
var grad1 = ctx.createRadialGradient(50, 50, 0, 50, 50, 50);
grad1.addColorStop(0, 'rgba(255, 252, 0, 1)');
grad1.addColorStop(1, 'rgba(68, 205, 37, 1)');
ctx.fillStyle = grad1;
ctx.fillRect(0, 0, 100, 100);
}
</script>
</head>
<body onload="draw();">
<div>
<canvas id="canvas" width="100" height="100"></canvas>
</div>
</body>
</html>
But the result is not quite what I want:
This should be done easily with a method like PathGradientBrush provided by GDI+.
I'm not sure is it possible with the HTML5 canvas element.
457
You could try to use a combination of linear gradient and clipping. Demo. Code:
var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
var outerColor = 'rgba(68,205,37,1)';
var innerColor = 'rgba(255,252,0,1)';
var w = 200;
var h = 50;
canvas.width = w;
canvas.height = h;
function gradient(dir) {
var grad = ctx.createLinearGradient(dir[0], dir[1], dir[2], dir[3]);
grad.addColorStop(0, outerColor);
grad.addColorStop(0.5, innerColor);
grad.addColorStop(1.0, outerColor);
return grad;
}
// idea: render background gradient and a clipped "bow"
function background() {
ctx.fillStyle = gradient([0, 0, 0, h]);
ctx.fillRect(0, 0, w, h);
}
function bow() {
ctx.save();
ctx.beginPath();
ctx.moveTo(0, 0);
ctx.lineTo(w, h);
ctx.lineTo(w, 0);
ctx.lineTo(0, h);
ctx.clip();
ctx.fillStyle = gradient([0, 0, w, 0]);
ctx.fillRect(0, 0, w, h);
ctx.restore();
}
background();
bow();
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