Reading Geotag data from image in php

Question

Does anyone know if there is a way to read geotag data from photos in PHP?

Thanks

Answer 1

Will Coughlin's answer is correct though I formulated a function for quick reference in case someone stumbles upon the same problem.

/**
 * Returns an array of latitude and longitude from the Image file
 * @param image $file
 * @return multitype:number |boolean
 */
function read_gps_location($file){
    if (is_file($file)) {
        $info = exif_read_data($file);
        if (isset($info['GPSLatitude']) && isset($info['GPSLongitude']) &&
            isset($info['GPSLatitudeRef']) && isset($info['GPSLongitudeRef']) &&
            in_array($info['GPSLatitudeRef'], array('E','W','N','S')) && in_array($info['GPSLongitudeRef'], array('E','W','N','S'))) {

            $GPSLatitudeRef  = strtolower(trim($info['GPSLatitudeRef']));
            $GPSLongitudeRef = strtolower(trim($info['GPSLongitudeRef']));

            $lat_degrees_a = explode('/',$info['GPSLatitude'][0]);
            $lat_minutes_a = explode('/',$info['GPSLatitude'][1]);
            $lat_seconds_a = explode('/',$info['GPSLatitude'][2]);
            $lng_degrees_a = explode('/',$info['GPSLongitude'][0]);
            $lng_minutes_a = explode('/',$info['GPSLongitude'][1]);
            $lng_seconds_a = explode('/',$info['GPSLongitude'][2]);

            $lat_degrees = $lat_degrees_a[0] / $lat_degrees_a[1];
            $lat_minutes = $lat_minutes_a[0] / $lat_minutes_a[1];
            $lat_seconds = $lat_seconds_a[0] / $lat_seconds_a[1];
            $lng_degrees = $lng_degrees_a[0] / $lng_degrees_a[1];
            $lng_minutes = $lng_minutes_a[0] / $lng_minutes_a[1];
            $lng_seconds = $lng_seconds_a[0] / $lng_seconds_a[1];

            $lat = (float) $lat_degrees+((($lat_minutes*60)+($lat_seconds))/3600);
            $lng = (float) $lng_degrees+((($lng_minutes*60)+($lng_seconds))/3600);

            //If the latitude is South, make it negative. 
            //If the longitude is west, make it negative
            $GPSLatitudeRef  == 's' ? $lat *= -1 : '';
            $GPSLongitudeRef == 'w' ? $lng *= -1 : '';

            return array(
                'lat' => $lat,
                'lng' => $lng
            );
        }           
    }
    return false;
}

Hope it helps someone.

Answer 2

Call this function with filename. I testet it and it works prefectly.

Call example:

$fileName='xxxxxx'; //or $fileName='xxxxxxxxx';
echo $returned_data = triphoto_getGPS($fileName);

Function:

function triphoto_getGPS($fileName)
{
    //get the EXIF all metadata from Images
    $exif = exif_read_data($fileName);
    if(isset($exif["GPSLatitudeRef"])) {
        $LatM = 1; $LongM = 1;
        if($exif["GPSLatitudeRef"] == 'S') {
            $LatM = -1;
        }
        if($exif["GPSLongitudeRef"] == 'W') {
            $LongM = -1;
        }

        //get the GPS data
        $gps['LatDegree']=$exif["GPSLatitude"][0];
        $gps['LatMinute']=$exif["GPSLatitude"][1];
        $gps['LatgSeconds']=$exif["GPSLatitude"][2];
        $gps['LongDegree']=$exif["GPSLongitude"][0];
        $gps['LongMinute']=$exif["GPSLongitude"][1];
        $gps['LongSeconds']=$exif["GPSLongitude"][2];

        //convert strings to numbers
        foreach($gps as $key => $value){
            $pos = strpos($value, '/');
            if($pos !== false){
                $temp = explode('/',$value);
                $gps[$key] = $temp[0] / $temp[1];
            }
        }

        //calculate the decimal degree
        $result['latitude']  = $LatM * ($gps['LatDegree'] + ($gps['LatMinute'] / 60) + ($gps['LatgSeconds'] / 3600));
        $result['longitude'] = $LongM * ($gps['LongDegree'] + ($gps['LongMinute'] / 60) + ($gps['LongSeconds'] / 3600));
        $result['datetime']  = $exif["DateTime"];

        return $result;
    }
}