Read the last line of a CSV file and extract one value

Question

New to Node.js and trying to pull a value from the very last line of a CSV file. Here is the CSV:

Unit ID,Date,Time,Audio File
Log File Created,3/6/2013,11:18:25 AM,file:\\\C:\Users\Ben\Documents\1_03-06-2013_1114-50.mp3
1,3/6/2013,11:20:24 AM,file:\\\C:\AlertLog\1_03-06-2013_1120-24.mp3
1,3/6/2013,11:20:39 AM,file:\\\C:\AlertLog\1_03-06-2013_1120-24.mp3

The part I am trying to grab is file:\\\C:\AlertLog\1_03-06-2013_1120-24.mp3 - preferably getting rid of the file:\\\ part.

Sorry that I do not have any code to show, just have a few hours of experience with Node.js and cannot seem to find any docs on how to accomplish something like this. Any help would be appreciated. Thanks!

Answer 1

Regular file

Read the file like a regular file, split the file contents into lines, take the last line, split by a comma and take the last part.

var fs = require('fs'); // file system module

fs.readFile('/path/to/file.csv', 'utf-8', function(err, data) {
    if (err) throw err;

    var lines = data.trim().split('\n');
    var lastLine = lines.slice(-1)[0];

    var fields = lastLine.split(',');
    var audioFile = fields.slice(-1)[0].replace('file:\\\\', '');

    console.log(audioFile);
});

File System module documentation

CSV parser

You can also use the node-csv-parser module.

var fs = require('fs');
var csv = require('csv');

csv()
 .from.stream(fs.createReadStream('/path/to/file.csv'))
 .to.array(function(data, count) {
    var lastLine = data.slice(-1)[0];
    var audioFile = lastLine.slice(-1)[0].replace('file:\\\\', '');
    console.log(audioFile);
  });