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Read next word in java

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What is next () method in Java?

next() method finds and returns the next complete token from this scanner. A complete token is preceded and followed by input that matches the delimiter pattern. This method may block while waiting for input to scan, even if a previous invocation of hasNext() returned true.

Does scanner next () return a String?

next(String pattern) method returns the next token if it matches the pattern constructed from the specified string.

How do I get a scanner to read the next line in Java?

nextLine() method advances this scanner past the current line and returns the input that was skipped. This method returns the rest of the current line, excluding any line separator at the end. The position is set to the beginning of the next line.

Does Java have next scanner?

The hasNext() method checks if the Scanner has another token in its input. A Scanner breaks its input into tokens using a delimiter pattern, which matches whitespace by default. That is, hasNext() checks the input and returns true if it has another non-whitespace character.


You do not necessarily have to split the line because java.util.Scanner's default delimiter is whitespace.

You can just create a new Scanner object within your while statement.

    Scanner sc2 = null;
    try {
        sc2 = new Scanner(new File("translate.txt"));
    } catch (FileNotFoundException e) {
        e.printStackTrace();  
    }
    while (sc2.hasNextLine()) {
            Scanner s2 = new Scanner(sc2.nextLine());
        while (s2.hasNext()) {
            String s = s2.next();
            System.out.println(s);
        }
    }

You already get the next line in this line of your code:

 String line = sc.nextLine();  

To get the words of a line, I would recommend to use:

String[] words = line.split(" ");

Using Scanners, you will end up spawning a lot of objects for every line. You will generate a decent amount of garbage for the GC with large files. Also, it is nearly three times slower than using split().

On the other hand, If you split by space (line.split(" ")), the code will fail if you try to read a file with a different whitespace delimiter. If split() expects you to write a regular expression, and it does matching anyway, use split("\\s") instead, that matches a "bit" more whitespace than just a space character.

P.S.: Sorry, I don't have right to comment on already given answers.


you're better off reading a line and then doing a split.

File file = new File("path/to/file");
String words[]; // I miss C
String line;
HashMap<String, String> hm = new HashMap<>();
try (BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(file), "UTF-8")))
{
    while((line = br.readLine() != null)){
        words = line.split("\\s");
        if (hm.containsKey(words[0])){
                System.out.println("Found duplicate ... handle logic");
        }
        hm.put(words[0],words[1]); //if index==0 is ur key
    }

} catch (FileNotFoundException e) {
        e.printStackTrace();
} catch (IOException e) {
        e.printStackTrace();
}

You can just use Scanner to read word by word, Scanner.next() reads the next word

try {
  Scanner s = new Scanner(new File(filename));

  while (s.hasNext()) {
    System.out.println("word:" + s.next());
  }
} catch (IOException e) {
  System.out.println("Error accessing input file!");
}