Read file with whitespace in its path using Java

Question

I am trying to open files with FileInputStream that have whitespaces in their names.

For example:

String fileName = "This is my file.txt";
String path = "/home/myUsername/folder/";

String filePath = path + filename;
f = new BufferedInputStream(new FileInputStream(filePath));

The result is that a FileNotFoundException is being thrown. I tried to hardcode the filePath to "/home/myUserName/folder/This\\ is\\ my\\ file.txt" just to see if i should escape whitespace characters and it did not seem to work. Any suggestions on this matter?

EDIT: Just to be on the same page with everyone viewing this question...opening a file without whitespace in its name works, one that has whitespaces fails. Permissions are not the issue here nor the folder separator.

Answer 1

File name with space works just fine

Here is my code

File f = new File("/Windows/F/Programming/Projects/NetBeans/TestApplications/database prop.properties");
        System.out.println(f.exists());
        try
        {
            FileInputStream stream = new FileInputStream(f);
        }
        catch (FileNotFoundException ex)
        {
            System.out.println(ex.getMessage());
        }

f.exists() returns true always without any problem

Answer 2

Looks like you have a problem rather with the file separator than the whitespace in your file names. Have you tried using

System.getProperty("file.separator")

instead of your '/' in the path variable?