I am making multiple calls with Promise.
My API endpoints to fetch are:
See the code
export function getTeamsStats(league, team, type) {
return function(dispatch) {
const url = "https://www.api-football.com/demo/v2/statistics";
let dates = ["2019-08-30", "2019-09-30", "2019-10-30"];
const getAllData = (dates, i) => {
return Promise.allSettled(dates.map(x => url + '/' + 357 + '/' + 5 + '/' + x).map(fetchData));
}
const fetchData = (URL) => {
return axios
.get(URL)
.then(res => {
const {
matchsPlayed: { total: teamsTotalMatchsPlayed},
} = res.data.api.statistics.matchs;
const matchsPlayed = teamsTotalMatchsPlayed;
dispatch(receivedTeamsStat(matchsPlayed, type));
})
.catch(e => {
console.log(e);
});
}
getAllData(dates).then(resp=>{console.log(resp)}).catch(e=>{console.log(e)})
}
}
Then in my component, I put in an array the matches played from this specific team ( Sao Paulo in this example ) from the initial date 30-8-2019 to 30-10-2019
const [dataHomeTeam, setDataHomeTeam] = useState([]);
useEffect(() => {
if (!team.matchsPlayed) {
return ;
}
setDataHomeTeam(prev =>
prev.concat([
{
matches: team.matchsPlayed,
}
])
);
},[team.matchsPlayed]);
console.log('Data Array', dataHomeTeam);
The problem is that normally the in the first render of the page I have the right order of the matches made from 30-8-2019 to 30-10-2019
See the console log image
But sometimes not, see here
So the question is, how can I make sure that the Promise is returning me the right order of the requests?
I am using Promise.allSettled
, the multiple asynchronous tasks that are not dependent on one another to complete successfully, but the order is not always right.
This should be resolved via Promise.all because as described in documentation
Returned values will be in order of the Promises passed, regardless of completion order.
The problem you have is that you are setting your state by calling dispatch
for each promise based on it's completion and since promises can finish at any given time (e.g. 3rd request could finish first because they are sent at the same time), dispatch
will be called and your state management will set that as first response (that's why you "sometimes" get such behaviour, because it's up to the network which one will finish first).
This would mean that either you should change your dispatch
to receive array of already finished promises, or call dispatch
one-by-one once they are finished which is shown in code below - resolve all and dispatch in order:
export function getTeamsStats(league, team, type) {
return function (dispatch) {
const url = "https://www.api-football.com/demo/v2/statistics";
let dates = ["2019-08-30", "2019-09-30", "2019-10-30"];
const getAllData = (dates, i) => {
return Promise.all(dates.map(x => url + '/' + 357 + '/' + 5 + '/' + x).map(fetchData));
}
const fetchData = (URL) => {
return axios
.get(URL)
.then(res => {
const {
matchsPlayed: { total: teamsTotalMatchsPlayed },
} = res.data.api.statistics.matchs;
return teamsTotalMatchsPlayed;
})
.catch(e => {
console.log(e);
});
}
getAllData(dates).then(resp => {
console.log(resp)
// 'resp' here are all 'teamsTotalMatchsPlayed' in correct order (here I mean order of call, not promise completion)
// so just dispatch them in order
resp.map(matchsPlayed => receivedTeamsStat(matchsPlayed, type));
}).catch(e => {
console.log(e)
})
}
}
Please note that I've maybe made some syntax error, but you get the idea.
The ideal way of achieving your requirment is by using Promise.all(). It is because of two main reasons,
Returned values will be in order of the Promises passed, regardless of completion order.
Refer to the Return value section in the link
This is also important as well. We don't need to wait for all the asynchronous iterable promises to be resolved/rejected, if the first iterable promise of fetchData rejects we can short circuit and reject the returned promise.
On the other hand Promise.allSettled(),
Promise.allSettled() method returns a promise that resolves after all of the given promises have either fulfilled or rejected, with an array of objects that each describes the outcome of each promise.
It also doesn't maintain the order in the returned promise.
Promise.allSettled() method never short-circuits. Always Promise fulfilled, never rejected.
Refer to the following comparison table between Promise.all() and Promise.allSettled(),
<script src="https://gist.github.com/Seralahthan/9934ba2bd185a8ccfbdd8e4b3523ea23.js"></script>
How, you have done,
function updateUI(value) {
console.log(value);
// Do something to update the UI.
}
// Note that order of resolution of Promises is 2, 1, 3
const promise1 = new Promise((resolve) => setTimeout(resolve, 200, 1)).then(updateUI);
const promise2 = new Promise((resolve) => setTimeout(resolve, 100, 2)).then(updateUI);
const promise3 = new Promise((resolve) => setTimeout(resolve, 300, 3)).then(updateUI);
const promises = [promise1, promise2, promise3];
Promise.allSettled(promises).
then((value) => console.log('Nothing to do here', value));
// Output: 2, 1, 3
// Here we update the UI as soon as the result is obtained. As a result, the UI is also updated in the
// order in which the promise was resolved.
In other words, we wait not only for the network call but we wait for both the network call and the UI update to complete for each id which is not you want.
How you should have done instead,
// Note that order of resolution of Promises is 2, 1, 3 (Same as previous)
const promise1 = new Promise((resolve) => setTimeout(resolve, 200, 1));
const promise2 = new Promise((resolve) => setTimeout(resolve, 100, 2));
const promise3 = new Promise((resolve) => setTimeout(resolve, 300, 3));
const promises = [promise1, promise2, promise3];
Promise.allSettled(promises).
then((results) => results.forEach((result) => updateUI(result.value)));
// Output: 1, 2, 3
// Here, we wait for all the network requests to complete and then loop through the results and update the UI.
// This ensures that the result is in order.
If you don't want to wait for all Promises to resolve and want to update the UI as soon as one resolves and still maintain order, then you need to pass the position of the element in the array and then use that position to update the element in place at the given position in the array.
Hope this helps.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With