I have a SideNav component that contains dynamically created links that need to scroll to a corresponding header in an adjacent html table (InfoTable). I've tried multiple different ways of accomplishing this to no avail.
export default class Parent extends Component {
state = {
categories: [],
}
scrollToHeader = (tableRefString) => {
// Function to pass to SideNav to access refs in InfoTable
this[tableRefString].scrollIntoView({ block: 'start' });
}
render() {
return (
<div>
<SideNav
categories={this.state.categories}
scrollToHeader={this.scrollToHeader} />
<InfoTable
categories={this.state.categories} />
</div>
);
}
}
export default class InfoTable extends Component {
render() {
return (
<div>
<table>
<tbody>
{this.props.categories.map(category => (
<>
// Forward the ref through InfoTableHeader to be set on the parent DOM node of each InfoTableHeader
<InfoTableHeader />
{category.inputs.map(input => <InfoTableRow />)}
</>
))}
</tbody>
</table>
</div>
);
}
}
In order to click a link on SideNav and scroll to the corresponding header on InfoTable, I believe that I need to forward refs that are dynamically created on Parent based on names in my categories array and set these refs to the DOM nodes for each header in InfoTable. From there I would pass a function to SideNav that could access the refs in Parent in order to scroll to the header.
I know there is an already accepted answer, and while I find @nicholas-haley's solution acceptable.
I think a better way to go about it would be to use the built-in useImperativeHandle
hook.
IMPORTANT: The React Hooks Api is available as of
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The React hooks API Docs state:
useImperativeHandle
customizes the instance value that is exposed to parent components when using ref. As always, imperative code using refs should be avoided in most cases. useImperativeHandle should be used with `forwardRef
This note is followed by the following example:
function FancyInput(props, ref) {
const inputRef = useRef();
useImperativeHandle(ref, () => ({
focus: () => {
inputRef.current.focus();
}
}));
return <input ref={inputRef} ... />;
}
FancyInput = forwardRef(FancyInput);
Thus, in my opinion, a much cleaner solution would be to delegate the needed refs through the useImperativeHandle
hook.
This way there is no need for a special ref syntax, and the component can simply return a specific type of a FatherRef; Example:
// LabelInput.js
function LabelInput(props, ref) {
const labelRef = useRef();
const inputRef = useRef();
useImperativeHandle(ref, () => ({
focus: () => {
inputRef.current.focus();
},
get input() {
return inputRef.current;
},
get label() {
return labelRef.current;
},
// ... whatever else one may need
}));
return (
<div>
<label ref={labelRef} ... />
<input ref={inputRef} ... />;
</div>
)
}
LabelInput = forwardRef(LabelInput);
function MyScreen() {
const labelInputRef = useRef();
const onClick = useCallback(
() => {
// labelInputRef.current.focus(); // works
// labelInputRef.current.input.focus(); // works
// ... etc
},
[]
);
return (
...
<LabelInput ref={labelInputRef} ... />
....
)
}
I actually just picked this up from react-hook-form, but they presented a nice way to share ref and assign multiple refs at once:
<input name="firstName" ref={(e) => {
register(e) // use ref for register function
firstNameRef.current = e // and you can still assign to ref
}} />
I had a similar situation where I needed multiple refs to be forwarded to the child of my Parent component.
I still have not found an elegant solution, however you might try passing your refs as an object, and destructuring within the forwardRef
callback:
// Parent
ref={{
ref1: this.ref1,
ref2: this.ref2
}}
// Child
export default React.forwardRef((props, ref) => {
const { ref1, ref2 } = ref;
return (
<Child1
{...props}
ref={ref1}
/>
<Child2
{...props}
ref={ref2}
/>
);
});
I'm not a big fan of the naming here (I'd prefer ref
to be called refs
), but this works in case you're in a pinch.
EDIT:
In 2020 I believe @samer-murad's answer is the best solution to this problem.
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