Menu
i am having trouble understanding the difference between the R function rank and the R function order. they seem to produce the same output:
> rank(c(10,30,20,50,40)) [1] 1 3 2 5 4 > order(c(10,30,20,50,40)) [1] 1 3 2 5 4 Could somebody shed some light on this for me? Thanks
604
The rank function gives the rank of the values in a vector if the vector is sorted but in the same sequence as the original vector and the order function gives the position of the original value in the vector but in the sequence of the sorting in ascending order.
Data Visualization using R Programming The ranking of a variable in an R data frame can be done by using rank function. For example, if we have a data frame df that contains column x then rank of values in x can be found as rank(df$x).
sort() sorts the vector in an ascending order. rank() gives the respective rank of the numbers present in the vector, the smallest number receiving the rank 1. order() returns the indices of the vector in a sorted order. Hope this is helpful.
rank() function in R Language is used to return the sample ranks of the values of a vector. Equal values and missing values are handled in multiple ways.
set.seed(1) x <- sample(1:50, 30) x # [1] 14 19 28 43 10 41 42 29 27 3 9 7 44 15 48 18 25 33 13 34 47 39 49 4 30 46 1 40 20 8 rank(x) # [1] 9 12 16 25 7 23 24 17 15 2 6 4 26 10 29 11 14 19 8 20 28 21 30 3 18 27 1 22 13 5 order(x) # [1] 27 10 24 12 30 11 5 19 1 14 16 2 29 17 9 3 8 25 18 20 22 28 6 7 4 13 26 21 15 23 rank returns a vector with the "rank" of each value. the number in the first position is the 9th lowest. order returns the indices that would put the initial vector x in order.
The 27th value of x is the lowest, so 27 is the first element of order(x) - and if you look at rank(x), the 27th element is 1.
x[order(x)] # [1] 1 3 4 7 8 9 10 13 14 15 18 19 20 25 27 28 29 30 33 34 39 40 41 42 43 44 46 47 48 49 If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
