Random number function python that includes 1?

Question

I am new to Python and am trying to create a program for a project- firstly, I need to generate a point between the numbers 0-1.0, including 0 and 1.0 ([0, 1.0]). I searched the python library for functions (https://docs.python.org/2/library/random.html) and I found this function:

random.random()

This will return the next random floating point number in the range [0.0, 1.0). This is a problem, since it does not include 1. Although the chances of actually generating a 1 are very slim anyway, it is still important because this is a scientific program that will be used in a larger data collection.

I also found this function:

rand.randint

This will return an integer, which is also a problem.

I researched on the website and previously asked questions and found that this function:

random.uniform(a, b)

will only return a number that is greater than or equal to a and less than b.

Does anyone know how to create a random function on python that will include [0, 1.0]?

Please correct me if I was mistaken on any of this information. Thank you.

*The random numbers represent the x value of a three dimensional point on a sphere.

Answer 1

Could you make do with something like this?

random.randint(0, 1000) / 1000.0

Or more formally:

precision = 3
randomNumber = random.randint(0, 10 ** precision) / float(10 ** precision)