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I am using the catch-all url pattern in my Flask route. I want the view to ignore (throw a 404 error) any path that starts with /api. How can I do this?
@app.route('/', defaults={'path': ''})
@app.route('/<path:path>')
def index(path):
return 'Hello, World!'
947
To handle 404 Error or invalid route error in Flask is to define a error handler for handling the 404 error. @app. errorhandler(404) def invalid_route(e): return "Invalid route." Now if you save the changes and try to access a non existing route, it will return “Invalid route” message.
App Routing means mapping the URLs to a specific function that will handle the logic for that URL. Modern web frameworks use more meaningful URLs to help users remember the URLs and make navigation simpler. Example: In our application, the URL (“/”) is associated with the root URL.
A 404 Error is showed whenever a page is not found. Maybe the owner changed its URL and forgot to change the link or maybe they deleted the page itself. Every site needs a Custom Error page to avoid the user to see the default Ugly Error page.
Check if the path starts with the prefix, then abort if it does.
from flask import abort
if path.startswith('api'):
abort(404)
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