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Ok so I have a problem with rails and rendering partials. I have a layout called profile and inside of the profile layout I have all my js, stylesheets, etc included.
<html>
<head>
<title>Profile</title>
<%= javascript_include_tag "https://ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js" %>
<%= javascript_include_tag "https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.10/jquery-ui.min.js" %>
<%= javascript_include_tag "application" %>
<%= stylesheet_link_tag "main" %>
<%= stylesheet_link_tag "reset" %>
<%= csrf_meta_tag %>
</head>
<body>
<%= yield %>
</body>
</html>
Inside of the yield tag(profile/index.html.erb) above is the following
<%= render :partial => 'pages/page', :layout => "layouts/default", :locals => {:page => @page } %>
Now in the pages/page view there are the same default tags such as css and js files. When i remove the css styles then I lose the styling for the pages/page view. Is there a way I can render a partial without recalling the same css and js files or what is a better way to go about doing something like so?
219
I always create the option to overwrite the stylesheets as follows:
<%= stylesheet_link_tag content_for?(:stylesheets) ? yield(:stylesheets) : "application", :debug => Rails.env.development? %>
Then inside a view
<% content_for :stylesheets %> some stuff or nothing in here <% end %>
That will let you specify in a view rendered in a layout you want no stylesheets and the same principle applies for javascripts.
That having been said if you are rendering a partial inside a layout that has an html tag and head etc. you should probably investigate if there is a better way to do what you are doing.
152
You need to pick one or the other: layout the original method call, or pass a layout to the partials. Doing both would be illogical.
There is a more thorough discussion here:
http://www.mikemayo.org/2012/rendering-a-collection-of-partials-with-content_for
28
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