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I have a question about arithmetic behaviour in R. Regard the following piece of code
> NaN + NA
[1] NaN
>
>
> NaN + as.integer(NA)
> NA
So, I am confused that these two additions give different results. Does anybody know if this is really wanted behaviour or just some kind of bug?
Thanks in advance
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In R, missing values are represented by the symbol NA (not available). Impossible values (e.g., dividing by zero) are represented by the symbol NaN (not a number).
nan() Function. is. nan() Function in R Language is used to check if the vector contains any NaN(Not a Number) value as element. It returns a boolean value for all the elements of the vector.
The NaN values are referred to as the Not A Number in R. It is also called undefined or unrepresentable but it belongs to numeric data type for the values that are not numeric, especially in case of floating-point arithmetic. To remove rows from data frame in R that contains NaN, we can use the function na. omit.
nan Function, Count, Replace & Remove. In the R programming language, NaN stands for Not a Number.
From ?NaN:
Computations involving
NaNwill returnNaNor perhapsNA: which of those two is not guaranteed and may depend on the R platform (since compilers may re-order computations).
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