Given the following named vector:
x <- c(54, 36, 67, 25, 76)
names(x) <- c('a', 'b', 'c', 'd', 'e')
How one can extract the elements between 'b' and 'd'? I can do that for data tables with the dplyr::select(dt, b:d) but for some reason, I cannot find a solution for named vectors (all the examples I find are for extracting element(s) by giving all the names not a range of names)...
You could do
x[which(names(x) == "b"):which(names(x) == "d")]
#> b c d
#> 36 67 25
The problem being that there is no guarantee in a named vector that names are unique, and if there are duplicate names the entire concept becomes meaningless.
If you wanted a complete solution that allows for tidyverse-style non-standard evaluation and sensible error messages you could have
subset_named <- function(data, exp)
{
if(missing(exp)) return(data)
exp <- as.list(match.call())$exp
if(is.numeric(exp)) return(data[exp])
if(is.character(exp)) return(data[exp])
tryCatch({
ss <- suppressWarnings(eval(exp))
return(data[ss])},
error = function(e)
{
if(as.character(exp[[1]]) != ":")
stop("`exp` must be a sequence created by ':'")
n <- names(data)
first <- as.character(exp[[2]])
second <- as.character(exp[[3]])
first_match <- which(n == first)
second_match <- which(n == second)
if(length(first_match) == 0)
stop("\"", first, "\" not found in names(",
deparse(substitute(data)), ")")
if(length(second_match) == 0)
stop("\"", second, "\" not found in names(",
deparse(substitute(data)), ")")
if(length(first_match) > 1) {
warning("\"", first,
"\" found more than once. Using first occurence only")
first_match <- first_match[1]
}
if(length(second_match) > 1) {
warning("\"", second,
"\" found more than once. Using first occurence only")
second_match <- second_match[1]
}
return(data[first_match:second_match])
})
}
That allows the following behaviour:
subset_named(x, "b":"d")
#> b c d
#> 36 67 25
subset_named(x, b:d)
#> b c d
#> 36 67 25
subset_named(x, 1:3)
#> a b c
#> 54 36 67
subset_named(x, "e")
#> e
#> 76
subset_named(x)
#> a b c d e
#> 54 36 67 25 76
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