'\r': command not found [duplicate]

Question

echo "Select your option:" echo "1. Change ip address" echo "2. Add route" echo "3. Reboot" echo "4. Exit" read A case $A in     1)             echo "Add Ip address"             read IP             echo "Add Netmask"             read Netid             echo "Add name of interface"             read Interface             ifconfig ${Interface} ${IP}/${Netid}             if [ $? -ne 0 ];then                     echo "Ip address not configured"             fi             ;;     2)             echo "Add Destination"             read dst             echo "Add Netmask"             read Netid             echo "Add Gateway"             read gw             route add $dst mask $Netid gw $gw             if [ $? -ne 0 ];then                     echo "Route not added"             fi             ;;     3)             reboot             ;;     4)             echo "Bye"             exit 0             ;;     default)             echo "Wrong selection"             exit 1 esac 

Error:

[b104@b104 Downloads]$ ./NetworkUtility.sh  ./NetworkUtility.sh: line 1: $'\r': command not found Select your option: 1. Change ip address 2. Add route 3. Reboot 4. Exit 1 ': not a valid identifier 7: read: `A ./NetworkUtility.sh: line 8: $'\r': command not found ./NetworkUtility.sh: line 9: syntax error near unexpected token `newline' '/NetworkUtility.sh: line 9: `case $A in  [b104@b104 Downloads]$  

Answer 1

It seems that you have Windows style line endings (\r\n) - you need to change them to unix style (\n). If you have dos2unix installed you could use it. You could also do it using sed or awk.