Quickest way to initialize an array of structures to all-0's?

Question

I'm trying to initialize an array of structures to all-0's, using the below syntax:

STRUCTA array[MAX] = {0}; 

However, I'm getting the following warning from gcc :

warning: missing braces around initializer

What am i doing wrong - is there another/better way to do this ?

Answer 1

It the first member of your struct has a scalar type, use

STRUCTA array[MAX] = {{ 0 }}; 

If the first member of your struct happens to be another struct object, whose first member has scalar type, then you'll have to use

STRUCTA array[MAX] = {{{ 0 }}}; 

and so on. Basically, you have to open a new level of nested {} every time you "enter" another nested aggregate (a struct or an array). So in this case as long as the first member of each nested aggregate is also an aggregate, you need to go deeper with {}.

All these extra braces are only there to avoid the warning. Of course, this is just a harmless warning (in this specific case). You can use a simple { 0 } and it will work.

Probably the the best way to deal with this is to disable this warning entirely (see @pmg's answer for the right command-line option). Someone working on GCC wasn't thinking clearly. I mean, I understand the value of that warning (and it can indeed be very useful), but breaking the functionality of { 0 } is unacceptable. { 0 } should have been given special treatment.

Answer 2

gcc is being a nuisance. It should accept that without warnings.
Try this

STRUCTA array[MAX] = {{0}}; 

That gcc behaviour can be controlled with the option -Wmissing-braces or -Wno-missing-braces.

-Wall enables this warning; to have -Wall but not the missing braces, use -Wall -Wno-missing-braces