Queuing optional AJAX/function calls in jQuery ($.Deferred)?

Question

I'm looking to queue an arbitrary number of possibly optional function calls in JavaScript/jQuery. For example, I may need to ensure the user is authenticated and a cookie is set before running a second (or third, fourth, etc.) function or AJAX call.

I looked into doing this with the recently added jQuery.Deferred, but found that it doesn't matter what order the calls are fired in (true async style). Also, I read that once a Deferred instance has been resolved, it's not possible to un-resolve it.

Here's where I'm at with this at the moment. Initially, I was thinking of setting the Deferred instance to resolved, then un-resolving it if an optional function came up in the stack.

var d = $.Deferred(),
    chained = d,
    d.resolve(),
    div = extra.find( "div:first" );

if ( extra.attr( "requires-auth" ) != undefined && !config.user_is_authenticated )
  chained = chained.pipe( authenticate );

if ( div.length )
  chained = chained.pipe( prepareExtra( div ) );

// When the two optional methods are resolved, show the content
chained.done( function() {
  extra.fadeIn( 500 )
} );

My question is, what is the best way to queue (0 to N) AJAX calls in pure JavaScript/jQuery? (without using plug-ins).

Tak!

Edit 2: SOLVED! Here's some working examples of this, one w/o AJAX and one with: https://gist.github.com/1021429 https://gist.github.com/1021435

Answer 1

Try resolving your initial Deferred as the very last thing:

var d = $.Deferred(),
    chained = d;

// optionally chain callbacks with chained = chained.pipe
if (condition) {
    chained = chained.pipe(function () {
        return $.ajax({...}); // Must return a new Promise
    });
}

chained.done(function () {
    // all chains should be processed now
});

d.resolve(); // finally, resolve the initial Deferred