I am currently using Visual Studio Express C++ 2008, and have some questions about catch block ordering. Unfortunately, I could not find the answer on the internet so I am posing these questions to the experts.
I notice that unless catch (...) is placed at the end of a catch block, the compilation will fail with error C2311. For example, the following would compile:
catch (MyException)
{
}
catch (...)
{
}
while the following would not:
catch (...)
{
}
catch (MyException)
{
}
a. Could I ask if this is defined in the C++ language standard, or if this is just the Microsoft compiler being strict?
b. Do C# and Java have the same rules as well?
c. As an aside, I have also tried making a base class and a derived class, and putting the catch statement for the base class before the catch statement for the derived class. This compiled without problems. Are there no language standards guarding against such practice please?
2. The order of catch blocks does matter. If the protected code can throw different exceptions which are not in the same inheritance tree, i.e. they don't have parent-child relationship, the catch blocks can be sorted any order.
The order of catch statements is important. Put catch blocks targeted to specific exceptions before a general exception catch block or the compiler might issue an error. The proper catch block is determined by matching the type of the exception to the name of the exception specified in the catch block.
When exception happens in the method, a special method exception table is checked, it contains records for each catch block: exception type, start instruction and end instruction. If the order of exception is incorrect, some catch block would be unreachable.
As is documented, try/catch blocks can't handle StackOverflowException and OutOfMemoryException.
According to the standard, the order is significant. Basically the first catch that matches the exception will be caught.
a) Because catch(...)
will make any following catches irrelevant, the standard only allows it to be the last catch.
b) C# and Java have similar rules.
c) catch (by reference or pointer) of a base before a derived class will make the code for the derived irrelevant. However, the standard does allow this
From C++ Standard 15.3/5 "Handling an exception":
The handlers for a try block are tried in order of appearance. That makes it possible to write handlers that can never be executed, for example by placing a handler for a derived class after a handler for a corresponding base class.
A
...
in a handler’s exception-declaration functions similarly to...
in a function parameter declaration; it specifies a match for any exception. If present, a...
handler shall be the last handler for its try block.
The so called default handler catch(...)
must be the last handler in the list of handlers. This is indeed required by the standard. However, this requirement is specific to default handler.
Otherwise the standard does not restrict the ordering of the handlers, meaning that generally you can create a handler that would "intercept" all exceptions that would otherwise reach some other handler down the list (thus making the latter handler useless).
Moreover, it is perfectly legal to repeat the same catch
clause (with the same type) several times
catch (int) {
// ...
}
catch (int) {
// ...
}
even though only the first one will have a chance of ever catching anything. A good compiler will issue a warning for cases like that, but formally it is not an error.
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