Query to order by the last three characters of a column

Question

Query the name of any student in STUDENTS who scored higher than 75 marks. Order your output by the last three characters of each name. If two or more students both have names ending in the same last three characters (i.e.: "Bobby", "Robby", etc.), secondary sort them by ascending ID.

STUDENTS table has following columns:

ID , NAME , MARKS

Sample input:

id         name     marks 1          ashley   81 2          samantha 75 3          julia    76 4          belvet   84 

Sample output:

Ashley Julia Belvet 

Explanation:

Only Ashley, Julia, and Belvet have marks > 75. If you look at the last three characters of each of their names, there are no duplicates and 'ley' < 'lia' < 'vet'.

This is correct output:

select name from students where marks>75

order by substr(name, -3, 3), id;

Answer 1

Try with this for MySQL:

SELECT NAME FROM STUDENTS WHERE Marks > 75 ORDER BY RIGHT(NAME, 3), ID ASC; 

Answer 2

If two or more students both have names ending in the same last three characters (i.e.: Bobby, Robby, etc.), secondary sort them by ascending ID. That's why ORDER BY ID is needed.

For MySQL:

SELECT Name FROM STUDENTS WHERE Marks>75 ORDER By SUBSTRING(Name,-3,LENGTH(Name)),ID 

Reference: MySQL SUBSTRING() function

For Oracle:

SELECT Name FROM Students WHERE Marks > 75 ORDER BY substr(Name, -3), ID;